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If x minus under root 2 is a zero of x square + root2x + k then find the value of k |
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Answer» k=-4 Step-by-step EXPLANATION: x-√2=0 x=√2 f(√2)=(√2)^2+√2(√2)+k f(√2)=0 √2^2+√2(√2)+k=0 2+2+k=0 k=-4 |
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