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If x = log sin 0, y = log cosec 0, then what is value of (x + y)2 |
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Answer» Answer: Given that y=log(sinx), we need to find the value of dx dy
We know that the derivative of log(X) w.r.t x is x 1
⟹ dx dy
= dx d
(log(sinx))= sinx 1
× dx d
(sinx)= sinx 1
×cosx=cotx Hence, dx dy
=cotx please follow me for getting your answers quickly and WATCHING funny MEMES everyday |
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