1.

If x = log sin 0, y = log cosec 0, then what is value of (x + y)2​

Answer»

Answer:

Given that y=log(sinx), we need to find the value of

dx

dy

We know that the derivative of log(X) w.r.t x is

x

1

dx

dy

=

dx

d

(log(sinx))=

sinx

1

×

dx

d

(sinx)=

sinx

1

×cosx=cotx

Hence,

dx

dy

=cotx

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