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If x/b-c=y/c-a=z/a-b then show that ax+by+cy=0please give me the answer as I have exams |
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Answer» Answer: Given, x/b-c=y/c-a=z/a-b=m(say) then x=m(b-c) y=m(c-a) z=m(a-b) now L.HS= ax+by+cy =am(b-c)+BM(c-a)+cm(a-b) =amb-amc+bmc-bma+cma-cmb =0 =R.HS |
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