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If `x/alpha+y/beta=1` touches the circle `x^2+y^2=a^2` then point `(1/alpha , 1/beta)` lies on (a) straight line (b) circle (c) parabola (d) ellipseA. a straight lineB. a circleC. a parabolaD. an ellipse |
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Answer» Correct Answer - B If `(x)/(alpha)+(y)/(beta)=1` touches the circle `x^(2)+y^(2)=a^(2)`, then `|((0)/(alpha)+(0)/(beta))/(sqrt((1)/(alpha^(2))+(1)/(beta^(2))))|=arArr (1)/(alpha^(2))+(1)/(beta^(2))=(1)/(a^(2))` `rArr((1)/(alpha),(1)/(beta))` lies on `x^(2)+y^(2)=(1)/(a^(2))`, which represents a circle. |
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