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If `x=A sin(omegat+(pi)/(6))`, then find the minimum time t when kinetic energy of SHM is same as its potential energy.A. `(pi)/(omega)`B. `(2pi)/(omega)`C. `(pi)/(6omega)`D. `(pi)/(12omega)` |
| Answer» `t=((pi)/(4)-(pi)/(6))/(omega)=(2pi)/(24omega)=(pi)/(12omega)` | |