If (x−a)2+(y−b)2=c2, for some c>0, prove that [1+(dydx)2]32d2ydx2 – InterviewSolution

1.	If (x−a)2+(y−b)2=c2, for some c>0, prove that [1+(dydx)2]32d2ydx2 is a constant independent of a and b.
Answer» If $(x - a)^{2} + (y - b)^{2} = c^{2},$ for some $c > 0,$ prove that $\frac{{[1 + {(\frac{d y}{d x})}^{2}]}^{\frac{3}{2}}}{\frac{d^{2} y}{d x^{2}}}$ is a constant independent of $a$ and $b$ .

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