If x=√7 +√5, show that x-x/4=2√3.

1.	If x=√7 +√5, show that x-x/4=2√3.
Answer» ANSWER: $x = \sqrt{7} + \sqrt{5} \\ 1/x = 1/ \sqrt{7} + \sqrt{5} \times \sqrt{7} - \sqrt{5}/ \sqrt{7} - \sqrt{5} \\ \sqrt{7} - \sqrt{5} /( \sqrt{7} ) {}^{2} - ( \sqrt{5} ) {}^{2} \\ \sqrt{7} - \sqrt{5}/ 7 - 5 \\ \sqrt{7} - \sqrt{5}/ 2 \\ x + 1/x = \sqrt{7} + \sqrt{5} - \sqrt{7} - \sqrt{5}/ 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{7} + \sqrt{5} /2$

Answer»

$x = \sqrt{7} + \sqrt{5} \\ 1/x = 1/ \sqrt{7} + \sqrt{5} \times \sqrt{7} - \sqrt{5}/ \sqrt{7} - \sqrt{5} \\ \sqrt{7} - \sqrt{5} /( \sqrt{7} ) {}^{2} - ( \sqrt{5} ) {}^{2} \\ \sqrt{7} - \sqrt{5}/ 7 - 5 \\ \sqrt{7} - \sqrt{5}/ 2 \\ x + 1/x = \sqrt{7} + \sqrt{5} - \sqrt{7} - \sqrt{5}/ 2 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{7} + \sqrt{5} /2$

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If x=√7 +√5, show that x-x/4=2√3.​

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If x=√7 +√5, show that x-x/4=2√3.