1.

If x=3 ,y=-2,z=0 then find the value of x3+y3+z3

Answer»

ANSWER:

X = 3

y = -2

z = 0

x^{3}+y^{3}+z^{3}=3xyz\\\\x^{3}+y^{3}+z^{3}=3(3)(-2)(0)\\\\x^{3}+y^{3}+z^{3}=0



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