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If x=3+underroot8, then find value of (x square +1/2x square) |
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Answer» Answer: x=3+underoot8 squaring both side x^2=[3+underoot8]^2 x^2=9+8+6root8 x^2=17+6root8 now 1/2x^2 =1/{2[17+6root8]} 1/[34+12root8] rationalise [34-12root8]/[34^2-12root8^2] [34-12root8]/[1156-1152] [34-12root8]/4 now ACCORDING to question x^2+1/2x^2 =17+6root8+34/4-12root8/4 =25.5+3root8 =25.5+6root8 ans Step-by-step EXPLANATION: |
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