If x^{3}+8 x^{2}+k x+18 is completely divisible byx+3 then the value o – InterviewSolution

1.	If x^{3}+8 x^{2}+k x+18 is completely divisible byx+3 then the value of k.
Answer» as its divisible by X+3hence X=-3put in the value in equation and equate to zero(-3)^3+8(-3)^2+k(-3)+18-27+72-3k+18=03k=63k=21

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