1.

If X + 2Y=8 and XY=2; find the value of x^2+ 4 y^2

Answer»

Answer:

56

Step-by-step explanation:

Solve this using the FORMULA (a+b)^2=a^2+b^2+2ab

LET a be x

And let b be 2Y

(x+2y)^2 =x^2+(2y) ^2+2*x*2y

8^2= x^2+4y^2+4*2

x^2+4y^2=64-8

=56


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