1.

If x=2y+6,find the value ofX^3-8Y^3-36XY-216

Answer»

X=2y+6 .then x-2y-6=0
now VALUE of x^3-8y^3-36xy-216=0
(x)^3-(2y)^3-(6)^6+3(x×2y×-6)=0
(x-2y-6)(x^2+4y^2+36-4xy+24y-12x)=0

putting the value of (x-2y-6)=0
then
0×(x^2+4y^2+36-4xy+24y-12x)=0 ANS.



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