X=2y+6 .then x-2y-6=0now VALUE of x^3-8y^3-36xy-216=0(x)^3-(2y)^3-(6)^6+3(x×2y×-6)=0(x-2y-6)(x^2+4y^2+36-4xy+24y-12x)=0putting the value of (x-2y-6)=0then0×(x^2+4y^2+36-4xy+24y-12x)=0 ANS.
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