1.

If x=√2is a solution of kx2+√2x+4=0 then find the value of k​

Answer»

Answer:

value of k = -3

Step-by-step EXPLANATION:

equation = kx² + √2x + 4

and we are GIVEN that x = √2

so we will PUT the value here..

k(√2)² + √2*√2 + 4 = 0

2k + 2 + 4 = 0

2k + 6 = 0

2k = -6

k = -6/2 = -3

Hence the value of k is -3



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