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If x=√2is a solution of kx2+√2x+4=0 then find the value of k |
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Answer» Answer: value of k = -3 Step-by-step EXPLANATION: equation = kx² + √2x + 4 and we are GIVEN that x = √2 so we will PUT the value here.. k(√2)² + √2*√2 + 4 = 0 2k + 2 + 4 = 0 2k + 6 = 0 2k = -6 k = -6/2 = -3 Hence the value of k is -3 |
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