1.

If X = (2) + underoot (3 )find thevalue of( x )square + (1 )upon (X) square answer /SOLVE IT PLEASE/

Answer»

X=2√3
x^2+1/x^2=
[2√3]^2+1/(2√3)^2
(2^2+{√3^2}+2×2√3)+(1/2^2+{√3}^2+2×2√3
(4+3+4√3)+1/4+3+4√3
On rationalising
7+4√3+[1/【7+4√3】]×7-4√3/6-4√3
7+4√3+7-4√3/(7)^2-(4)^2(√3)^2
7+4√3+7-4√3/49-(16×3)
7+4√3+7-4√3/49-48
7+4√3+7-4√3/1
On cancellation
7+7
=14


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