1.

If x^2 - px + 12 =(x-3)(x-a) is an identify, then find the values of a and p​

Answer»

<P>Answer:

x^2 - PX + 12 = ( x - 3)( x -a )

x^2 - px +12 = x^2 - 3x -ax + 3A

x^2 - px + 12 = x^2 - ( 3 + a ) x + 3a

Therefore, p = 3 + a, 3a = 12

a = 4; p = 3+ 4 = 7


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