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If x=2 and x =3/4 are the solution to the equation px2+qx-6=0 find the value of p and q |
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Answer» Answer: if x = 2 px^2 + qx + 6 = 0 p(2)^2 + 2q + 6 = 0 4p + 2q + 6 = 0.........(i) if x = 3/4 px^2 + qx + 6 = 0 p(3/4)^2 + q(3/4) + 6 = 0 p(9/16) + 3q/4 + 6 = 0 9p/16 + 12q/16 + 96/16 = 0 9p+12q+96/16 = 0 16 is in the denominator so it 9p + 12q + 96 = 0 ........ (ii) will multiply with 0 = 0*16 = 0 (i) eqn * 6 24p + 12q + 36 = 0 24p + 12q + 36 = 0 -9p + 12q + 96 = 0 .................................... 15 p - 60 = 0 ................................... 15P - 60 = 0 15p = 60 p = 4 4p + 2q + 6 = 0 4(4) + 2q + 6 = 0 16 + 2q + 6 = 0 32 + 2q = 0 2q = -32 q = -16 hope it HELPS!!!!!!! plz mark me as BRAINLIEST!!!!!!!! |
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