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If x=2/3 and x=-3 are root of the quadratic equationfind the value of a and b |
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Answer» Step-by-step explanation: PUT the value of X to find a and b
a(2/3)^2+(2/3)+b=0 4a/9+2/3+b=0 4a+6+9b=0 EQUATION one a(-3)^2+b+(-3)=0 9a-3+b=0 equation 2 from equation 1 and 2 4a+9b+6=0 9×(9a+b-3=0) 81a+9b-27=0 -(4a+6+9b=0) 77a-33=0 a=3/7 put value of a to find b 12/7+6+9b=0 9b=(-54/7) b=(-6/7) |
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