If x=√2-1/√2+1 and y=√2+1/√2-1, then find the value of x²+5xy

1.	If x=√2-1/√2+1 and y=√2+1/√2-1, then find the value of x²+5xy + y² hint :x²+5xy+y²=(x+y²) +3xy
Answer» RATIONALISING the DENOMINATOR of the VALUE of X and y we get x=3-2√2 y=3+2√2 therefore , (x+y)² +3XY = (3-2√2+3+2√2)²+3×(3-2√2)(3+2√2) =6²+3×3²-(2√2)² =36+3×1 =39

If x=√2-1/√2+1 and y=√2+1/√2-1, then find the value of x²+5xy + y² hint :x²+5xy+y²=(x+y²) +3xy

Answer»

RATIONALISING the DENOMINATOR of the VALUE of X and y we get

x=3-2√2 y=3+2√2

therefore ,

(x+y)² +3XY

= (3-2√2+3+2√2)²+3×(3-2√2)(3+2√2)

=6²+3×3²-(2√2)²

=36+3×1

=39

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If x=√2-1/√2+1 and y=√2+1/√2-1, then find the value of x²+5xy + y² hint :x²+5xy+y²=(x+y²) +3xy

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