1.

If x + 1 men will do the work in x + 1 days, find the number of days that (x + 2) men can finish the same work.

Answer»

Number of workers and number of days are in inverse proportion.

⇒ x1y1 = x2y2

⇒ (x + 1) (x + 1) = (x + 2) x k

⇒ k = ((x + 1)(x + 1)) / (x + 2)

∴ k = (x + 1)2/(x + 2)



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