1.

If (x+1) is a factor of x³ + 2x² - 5x - 6, find the other factors using long division.​

Answer»

ANSWER:

Let F(x)=x

3

−2x

2

−5x+6

⇒f(1)=1

3

−21

2

−5×1+6=1−2−5+6=0

Using synthetic DIVISION, we have

x

2

−x−6=0 is the other FACTOR

(x−1)(x

2

−x−6)=0

=(x−1)(x

2

−3x+2x−6)=0

=(x−1)(x(x−3)+2(x−3))=0

=(x−1)(x+2)(x−3) are the factors of f(x)



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