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If x+1 is a factor of ax³ + x²-2x+4a-9 then find the value of a |
Answer» ANSWER :-a = 2 Solution :-f(x) = ax³ + x² - 2X + 4a - 9 g(x) = x + 1 Find the zero of x + 1 To find zero of x + 1 equate x + 1 to zero x + 1 = 0 x = - 1 By factor theorem f(-1) = 0 f(-1) = 0 ⇒ a(-1)³ + (-1)² - 2(-1) + 4a - 9 = 0 ⇒ a(-1) + 1 + 2 + 4a - 9 = 0 ⇒ - 1a + 3 + 4a - 9 = 0 ⇒ 3a - 6 = 0 ⇒ 3a = 6 ⇒ a = 6/3 ⇒ a = 2 |
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