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If x = - 1 and x =2 are exterme points of the function y=a `log x + bx^(2) + x`, then-A. `a=2,b= 1//2`B. `a=2,b=-1//2`C. `a=-2,b= 1//2`D. `a=- 2, b=- 1//2` |
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Answer» Correct Answer - 2 `(dy)/(dx) = (a)/(x) + 2 bx +1` Since `x=-1` and `x=2` are extreme points so gy/dx at these points must be zero . So `- a - 2b + 1 = 0 and a//2 + 4b + 1 = 0` `rArr a+ 2b -1=0 and a+ 8b + 2=0` `rArr a= 2, b=- 1//2` |
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