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IF (x-1/3)³= x³-x²+ax=1/27 the valve of a is: |
Answer» a = 1/9Step-by-step EXPLANATION: (X-1/3)³= x³-x²+ax=1/27(x-1/3)³ = x³ - (1/3)³ - 3(x)(1/3)² + 3(x)²(1/3){ (a-b)^3 = a^3-b^3-3ab^2+3a^2b }(x-1/3)³ = x³ - 1/27 - 3x(1/9) + 3(x)²(1/3)(x-1/3)³ = x³ - 1/27 - x/9 + x²Given that,x³ - 1/27 - x/9 + x² = x³ - x² + ax - 1/27By COMPARING the coefficients of VARIABLES on both sides. We get,x³ = x³+ x² = + x²- 1/27 = - 1/27ax = x/9 => a = 1/9 |
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