If x = -1|2 , is a zero of the polynomial p(x)=8x cube - ax square - x

1.	If x = -1\|2 , is a zero of the polynomial p(x)=8x cube - ax square - x +2 , then find a.
Answer» P(x) = 8x^3 - ax^2 - x + 2 x = - 1/2 is a zero of polynomial Therefore,For x = - 1/2, given polynomial equal to zero 8(-1/2)^3 - a(-1/2)^2 - (-1/2) + 2 = 08(-1/8) - a(1/4) + 1/2 + 2 = 0- 1 - a/4 + 5/2 = 05/2 - 1 = a/4(5 - 2)/2 = a/43/2 = a/4a = 4*3/2 = 6

If x = -1|2 , is a zero of the polynomial p(x)=8x cube - ax square - x +2 , then find a.

Answer»

P(x) = 8x^3 - ax^2 - x + 2

x = - 1/2 is a zero of polynomial

Therefore,For x = - 1/2, given polynomial equal to zero

8*(-1/2)^3 - a*(-1/2)^2 - (-1/2) + 2 = 08*(-1/8) - a*(1/4) + 1/2 + 2 = 0- 1 - a/4 + 5/2 = 05/2 - 1 = a/4(5 - 2)/2 = a/43/2 = a/4a = 4*3/2 = 6