If x + 1 = 2 cosa, y + = 2 cos B, then xy +=1) cos(a + b) 2) 2 cos(a +

1.	If x + 1 = 2 cosa, y + = 2 cos B, then xy +=1) cos(a + b) 2) 2 cos(a +B)3) 2 sin(a +B) 4) sin(a +B)
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If x + 1 = 2 cosa, y + = 2 cos B, then xy +=1) cos(a + b) 2) 2 cos(a +B)3) 2 sin(a +B) 4) sin(a +B)

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Answer is 2

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If x + 1 = 2 cosa, y + = 2 cos B, then xy +=1) cos(a + b) 2) 2 cos(a +B)3) 2 sin(a +B) 4) sin(a +B)​

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If x + 1 = 2 cosa, y + = 2 cos B, then xy +=1) cos(a + b) 2) 2 cos(a +B)3) 2 sin(a +B) 4) sin(a +B)