If x > 0, y > 0, then tan-1 x + tan-1 y =(a) tan-1(x + y)(b) tan-1((x – InterviewSolution

1.	If x > 0, y > 0, then tan-1 x + tan-1 y =(a) tan-1(x + y)(b) tan-1((x + y)/(1 - xy))(c) tan-1(x - y)(d) sin-1(x + y)
Answer» Answer is (b) tan^-1((x + y)/(1 - xy))

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