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If work done in moving a charge of 20mC from infinity to a point O in an electric field is 15J , then what is the electric potential at this point?don't post offensive content ❌copied answer = ids reported |
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Answer» Answer: 750 V Step-by-step EXPLANATION: V=W\Q W=15J Q=20mC or 0.02C therefore,15J/0.02C =750V |
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