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If work done in moving a charge of 20mC from infinity to a point O in an electric field is 15J , then what is the electric potential at this point?don't post offensive content ❌copied answer = ids reported ​

Answer»

Answer:

750 V

Step-by-step EXPLANATION:

V=W\Q

W=15J

Q=20mC or 0.02C

therefore,15J/0.02C

=750V



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