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If we add 1*10-8 of HCl into pure water in the following reaction: HCl (aq) + H2O (l) to give H3O+ (aq) + Cl- (aq) and assuming that volume doesn't change when HCl is added, why is H3O+ = HCl = 10-8? Shouldn't it be H3O+ + HCl = 10-8 because HCl is dissolved with water? |
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Answer» If we add 1*10-8 of HCl into pure water in the following reaction: HCl (aq) + H2O (l) to give H3O+ (aq) + Cl- (aq) and assuming that volume doesn't change when HCl is added, why is H3O+ = HCl = 10-8? Shouldn't it be H3O+ + HCl = 10-8 because HCl is dissolved with water? |
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