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if w,x,y,z∈ R+ and 256xyzw≥slant{(w+x+y+z)}^4and 3w+5x+7y+9z=24,then roots of equation (w+x)t^2+yzt+\sqrt{x+y+w+z}=0 are |
| Answer» if w,x,y,z∈ R+ and 256xyzw≥slant{(w+x+y+z)}^4and 3w+5x+7y+9z=24,then roots of equation (w+x)t^2+yzt+\sqrt{x+y+w+z}=0 are | |