If velocity v of a particle moving on a straight lineas a function of

1.	If velocity v of a particle moving on a straight lineas a function of time t is given as v = 5-t (m/s)then the distance covered by the particle in first10 s is(1) 5 m(2) 15 m(3) 25 m(4) 50 m
Answer» Answer:25 m Explanation: Since the question is asking for DISTANCE So FIRST TAKE out the maximum TIME by putting v=0 t comes out to be 5S Now integrate the equation of velocity to get equation for displacement which comes out to be x = 5t -t^2/2 Now put 5 in the equation this will give displacement in 5s.For distance in next 5s multiply the result by two. Thus answer comes out to be 25. Solve it and if you have any doubt feel free to ask.

If velocity v of a particle moving on a straight lineas a function of time t is given as v = 5-t (m/s)then the distance covered by the particle in first10 s is(1) 5 m(2) 15 m(3) 25 m(4) 50 m

Answer»

Answer:25 m

Explanation:

Since the question is asking for DISTANCE

So FIRST TAKE out the maximum TIME by putting v=0

t comes out to be 5S

Now integrate the equation of velocity to get equation for displacement which comes out to be

x = 5t -t^2/2

Now put 5 in the equation this will give displacement in 5s.For distance in next 5s multiply the result by two.

Thus answer comes out to be 25.

Solve it and if you have any doubt feel free to ask.

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If velocity v of a particle moving on a straight lineas a function of time t is given as v = 5-t (m/s)then the distance covered by the particle in first10 s is(1) 5 m(2) 15 m(3) 25 m(4) 50 m​

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If velocity v of a particle moving on a straight lineas a function of time t is given as v = 5-t (m/s)then the distance covered by the particle in first10 s is(1) 5 m(2) 15 m(3) 25 m(4) 50 m