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If `veca, vecb,vecc` are unit vectors such that `veca.vecb = 0= veca.vecc` and the angle between `vecb and vecc is pi//3` then the value of `|vecaxxvecb -veca xx vecc|` isA. `1//2`B. 1C. 2D. none of these |
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Answer» Correct Answer - b `|vecaxxvecb-vecaxxvecc|^(2)=|vecaxx(vecb-vecc)|^(2)` `|veca|^(2)|vecb-vecc|^(2)` `-(veca.(vecb-vecc))^(2)=|vecb-vecc|^(2)` `= |vecb|^(2)+|vecc|^92)-2|vecb||vecc|cos (pi/3)=1` |
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