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If `vecA= 2hati-2hatj-hatk and vecB= hati+hatj`, then : (a) Find angle between `vecA and vecB`. (b) Find the projection of resultant vector of `vecA and vecB` on x-axis. |
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Answer» Correct Answer - (a) `90^(@)` (b) 3 (a) Let the angle between `vecA and vecB` is `theta`, then `cos theta = (vecA*vecB)/(AB) = ((2hati- 2hatj-hatk))/(|2hati+ 2hatj -hatk||hati+hatj|)= (0)/(3sqrt2) =0` `rArr theta = 90^(@)` (b) Resultant vector `(vecR)= vecA+ vecB= (2hati- 2hatj-hatk)+(hati+hatj)= 3hati-hatj-hatk` `therefore ` projection of resultant of x-axis = 3. |
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