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If `vecA=2hati-2hatj-hatk` and `vecB=hati+hatj`, then : (a) Find angle between `vecA` and `vecB`. (b) Find the projection of resultant vector of `vecA` and `vecB` on x-axis. (c) Find a vector which is, if added to `vecA, gives a unit vector along y-axis. |
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Answer» (a) Let the angle between `vecA` and `vecB` is `theta`, then `cos theta=(vecA.vecB)/(AB)=((2hati-2hatj-hatk).(hati+hatj))/(|2hati+2hatj-hatk|.|hati+hatj|)=(0)/(3sqrt(2))=0rArrtheta=90^(@)` (b) Resultant `(vecR)=vecA+vecB=(2hati-2hatj-hatk)+(hati+hatj)=3hati-hatj-hatk therefore` projection of resultant on x-axis =3 (c) Required vector `=hatj-vecA=hatj-(2hati-2hatj-hatk)=-2hati+3hatj+hatk` |
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