If v ml of the vapours of substance at ntp weight w g then molecular w

1.	If v ml of the vapours of substance at ntp weight w g then molecular weight of substance is
Answer» Mole = V / 22400 Mole = WEIGHT / Molecular weight So, V / 22400 = W / Molecular weight Therefore the molecular weight of the SUBSTANCE would be *= (W / V ) 22400**

If v ml of the vapours of substance at ntp weight w g then molecular weight of substance is

Answer»

Mole = V / 22400

Mole = WEIGHT / Molecular weight

So, V / 22400 = W / Molecular weight

Therefore the molecular weight of the SUBSTANCE would be

= (W / V ) * 22400