If V is the volume of a cuboid of dimensions a,b,c and S is its surface area then prove that1V=2S(1a+1b+1c).

If V is the volume of a cuboid of dimensions a,b,c and S is its surfac

1.	If V is the volume of a cuboid of dimensions a,b,c and S is its surface area then prove that1V=2S(1a+1b+1c).
Answer» $If V is the volume of a cuboid of dimensions a,b,c and S is its surface area then prove that \frac{1}{V} = \frac{2}{S} (\frac{1}{a} + \frac{1}{b} + \frac{1}{c}) .$