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If u=x2y, then relative error in u, when there is an error of 0.01 both in x, y at x=1=y, is |
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Answer» Step-by-step explanation: Given that: F=x ^2
Hence, DF/ dx =2x Therefore: Δf= df/dx Δx=2xΔx The relative ERROR in f is: Δf/f = 2xΔx/x^2
Δf/f = 2Δx/x
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