If two soap bubbles of radii r and 2r form a double bubble. Then the radius of curvature of the interface between the two bubbles will be(1) r/2(2) 2r(3) 3r(4) 20/3

If two soap bubbles of radii r and 2r form a double bubble. Then the r

1.	If two soap bubbles of radii r and 2r form a double bubble. Then the radius of curvature of the interface between the two bubbles will be(1) r/2(2) 2r(3) 3r(4) 20/3
Answer» Let say P 1 and P 2 are the excess pressure on the TWO SIDES of the interface then the resultant excess pressure is P⇒P=P 2 −P 1 ⇒ r4T = r 2 4T − r 1 4T ⇒ r1 = r 2 1 − r 1 1 ⇒ r= r 1 −r 2 r 1 r 1

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If two soap bubbles of radii r and 2r form a double bubble. Then the radius of curvature of the interface between the two bubbles will be(1) r/2(2) 2r(3) 3r(4) 20/3​

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If two soap bubbles of radii r and 2r form a double bubble. Then the radius of curvature of the interface between the two bubbles will be(1) r/2(2) 2r(3) 3r(4) 20/3