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If two circles and `a(x^2 +y^2)+bx + cy =0` and `A(x^2+y^2)+Bx+Cy= 0` touch each other, thenA. aC=cAB. bC=cBC. aB=bAD. a A=bB=cC |
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Answer» Correct Answer - B Clearly both are circles pass through the origin. The two circles will touch each other if they have a common tangent at the origin. The tangents at the origin to the two circles are bx+cy=0 and Bx+Cy=0. These two must be identical `:. (b)/(B)=(c)/(C)rArr bC=Bc` |
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