If two adjacent angles of parallelogram are 3x - 5 and 6x + 5 then fin

1.	If two adjacent angles of parallelogram are 3x - 5 and 6x + 5 then find the value of
Answer» Weknowthatthesumofadjacentanglesofaparallelogramis180°.⇒2x+25+3x−5=180⇒5x+20=180⇒5x=180−20⇒5x=160⇒x=1605⇒x=32Therefore,thevalueofxis32. In Parallelogram sum of two adjacent angles is 180° by the property of Co-interior angles Hence,(3x - 5) + (6x + 5) = 1809x = 180x = 180/9x = 20 Therefore,Value of x = 20

If two adjacent angles of parallelogram are 3x - 5 and 6x + 5 then find the value of

Answer»

Weknowthatthesumofadjacentanglesofaparallelogramis180°.⇒2x+25+3x−5=180⇒5x+20=180⇒5x=180−20⇒5x=160⇒x=1605⇒x=32Therefore,thevalueofxis32.

In Parallelogram sum of two adjacent angles is 180° by the property of Co-interior angles

Hence,(3x - 5) + (6x + 5) = 1809x = 180x = 180/9x = 20

Therefore,Value of x = 20