1.

if turns in primary are 100 and turns in secondary are 500 and voltage of 6 volt is applied at primary than what voltage will be at secondary?

Answer»

no. of turns of primary coil              N = 100no. of turns of SECONDARY coil          n=500voltage ACROSS primary coil               V= 6Vvoltage across secondary coil          v= ?Formula;                                                       100/500 = 6/v                                   v  =(6 X 500)/100                                      v =   30V Ans.



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