If triangle ABC is right angled at C then find the value of cos A+B

1.	If triangle ABC is right angled at C then find the value of cos A+B
Answer» ANSWER: The value of COS (A+B) is equal to 0. Step-by-step explanation: We know that a ""right ANGLED triangle"" is a triangle in which ONE angle is “90°” Given: ABC is a right angled triangle i.e. A+B +C = 90⁰ Therefore A + B =180⁰ -C =180⁰- 90⁰ A +B=90⁰ Adding Cos on both the sides [In a right angled triangle the ""cosine or cos of an angle"" is the length of side which is adjacent divided by the length of hypotenuse] Cos(A + B)=Cos(90⁰) =0 Step-by-step explanation:

Answer»

ANSWER:

The value of COS (A+B) is equal to 0.

Step-by-step explanation:

We know that a ""right ANGLED triangle"" is a triangle in which ONE angle is “90°”

Given: ABC is a right angled triangle

i.e. A+B +C = 90⁰

Therefore A + B =180⁰ -C

=180⁰- 90⁰

A +B=90⁰

Adding Cos on both the sides [In a right angled triangle the ""cosine or cos of an angle"" is the length of side which is adjacent divided by the length of hypotenuse]

Cos(A + B)=Cos(90⁰)

=0

Step-by-step explanation:

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If triangle ABC is right angled at C then find the value of cos A+B

Given: ABC is a right angled triangle

=0

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