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If trace of the matrix ⎡⎢⎣2x22x0x2−113x−4⎤⎥⎦ is given by Tr(A)=limn→0(2n+4n+8n3)1/n, then possible value(s) of x is(are) |
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Answer» If trace of the matrix ⎡⎢⎣2x22x0x2−113x−4⎤⎥⎦ is given by Tr(A)=limn→0(2n+4n+8n3)1/n, then possible value(s) of x is(are) |
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