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If three vertices of IIgm are given find other.​

Answer»

Answer:

Let A(- 1, 0), B(3, 1), C(2, 2) and D(x, y) be the vertices of a parallelogram ABCD TAKEN in order.

Since, the diagonals of a parallelogram bisect each other.

So, coordinate of the mid point of AC = coordinate of mid point of BD

⇒ [(-1 + 2)/2, (0 + 2)/2] = [(3 + x)/2, (y + 1)/2]

⇒ (1/2, 1) = [(3 + x)/2, (y + 1)/2]

(3 + x)/2 = ½ ⇒ x = - 2

Also (y + 1)/2 = 1 ⇒ y + 1 = 2

⇒ y = 1

The fourth vertex of parallelogram = (- 2, 1).


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