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If three positive numbers `a,b` and c are in AP, GP and HP as well, than find their values. |
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Answer» Since, `a,b,c` are in AP,GP and HP as well `therefore " " b=(a+c)/(2) " " "…..(i)"` ` " " b^(2)=ac " " "…..(ii)"` and `b= (2ac)/(a+c)" " "…..(iii)"` Form Eq. (i) and (ii), we have `((a+c))^(2)/(2)` or `(a+c)^(2)=4ac` or `(a+c)^(2)-4ac=0` or `(a-c)^(2)=0` `therefore " "a=c " " "........(iv)"` On putting `c=a` in Eq. (i), we get `b=(a+a)/(2)=a " " "......(v)"` From Eqs. (iv) and (v), `a=b=c`, thus the three numbes will be equal. |
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