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If three parabols touch all the lines `x = 0, y = 0` and `x +y =2`, then maximum area of the triangle formed by joining their foci isA. `sqrt(3)`B. `sqrt(6)`C. `(3sqrt(3))/(4)`D. `(3sqrt(3))/(2)` |
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Answer» Correct Answer - D Let ABC be a triangle whose sides are `x =0, y =0` and `x +y = 2`. Since, the parabols touch the side, so foci must lie on circumcircle of the triangle ABC whose radius is `sqrt(2)`. Now, foci form a triangle of maximum area. Hence, foci must be the vertices of an equilateral triangle inscribed in the circumcircle. So, area `= (sqrt(3))/(4) (sqrt(3)sqrt(2))^(2) = (3sqrt(3))/(2)`. |
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