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If three error in the measurement of radius is 2% then the error in tge determination of volume of the sphere |
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Answer» Answer: 6% Explanation: Percentage error in RADIUS is GIVEN as 2% i.e. r Δr ×100=2 % 3 4π r 3
Percentage error in volume V ΔV ×100=3× r Δr ×100=3×2=6 % |
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