1.

If three error in the measurement of radius is 2% then the error in tge determination of volume of the sphere​

Answer»

Answer:

6%

Explanation:

Percentage error in RADIUS is GIVEN as 2% i.e.    

r

Δr

×100=2 %

VOLUME of sphere   V=  

3

r  

3

 

Percentage error in volume    

V

ΔV

×100=3×  

r

Δr

×100=3×2=6 %



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