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If `theta`is the angle between the two radii (one to each circle) drawn from oneof the point of intersection of two circles `x^2+y^2=a^2`and `(x-c)^2+y^2=b^2,`then prove that the length of the common chord of the two circles is `(2a bsintheta)/(sqrt(a^2+b^2-2a bcostheta))`A. `(ab)/(sqrt(a^(2)+b^(2)-2ab cos theta))`B. `(2ab)/(sqrt(a^(2)+b^(2)-2ab cos theta))`C. `(2ab sin theta)/(sqrt(a^(2)+b^(2)-2ab cos theta))`D. `(2ab cos theta)/(sqrt(a^(2)+b^(2)-2ab cos theta))`

Answer» Correct Answer - C


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