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If the zeroes of the polynomial x^2 + px + q are double in value to the zeroes of2x^2 - 5x -3, find the value of p

Answer»

Answer

p = -5, q = -6

Step-by-step explanation:

2x²-5x-3 = 2x²-6x+x-3

             = 2X(x-3)+1(x-3)

             = (x-3)(2x+1)

HENCE, the zeros of 2x²-5x-3 are -1/2 and 3.

Zeros of the polynomial x²+px+q  are double in value to -1/2 and 3,

THUS zeros are -1 and 6.

Now, quadratic expression with zeros -1 and 6 is given by

(x + 1)(x-6) = x²-5x-6. By comparison, p = -5 and q = -6.


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