if the zeroes of the polynomial (k^2 + 1) x^2 +5x+2k are reciprocals o

1.	if the zeroes of the polynomial (k^2 + 1) x^2 +5x+2k are reciprocals of each other find the zeros
Answer» Let zeroes of polynomial (k^2+1)x^2 + 5x + 2k are n and m Then,n = 1/mnm = 12k/(k^2 + 1) = 12k = k^2 + 1k^2 - 2k + 1 = 0k^2 - k - k + 1 = 0k(k - 1) - 1(k - 1) = 0(k - 1)(k-1) = 0k = 1 Put value of k =1 in given equation, we get2x^2 + 5x + 2 = 02x^2 + 4x + x + 2 = 02x(x + 2) + 1(x + 2) = 0(2x + 1)(x + 2) = 0x = - 1/2, - 2 Therefore, Zeros are - 1/2 and - 2

if the zeroes of the polynomial (k^2 + 1) x^2 +5x+2k are reciprocals of each other find the zeros

Answer»

Let zeroes of polynomial (k^2+1)x^2 + 5x + 2k are n and m

Then,n = 1/mnm = 12k/(k^2 + 1) = 12k = k^2 + 1k^2 - 2k + 1 = 0k^2 - k - k + 1 = 0k(k - 1) - 1(k - 1) = 0(k - 1)(k-1) = 0k = 1

Put value of k =1 in given equation, we get2x^2 + 5x + 2 = 02x^2 + 4x + x + 2 = 02x(x + 2) + 1(x + 2) = 0(2x + 1)(x + 2) = 0x = - 1/2, - 2

Therefore, Zeros are - 1/2 and - 2