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If the zero of the qurdratic polynomial x^2+(a+1)x+b are 2 and -3 then a,b values are |
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Answer» a=0,b=-6 Step-by-step EXPLANATION: -(a+1)=2-3 -a-1=-1 a=0 c÷a=b 2×-3=-6 (MULTIPLICATION of ROOTS) b=-6 |
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